a=3419(1+.041/12)^36

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Solution for a=3419(1+.041/12)^36 equation: 



a=3419(1+.041/12)^36

We move all terms to the left:

a-(3419(1+.041/12)^36)=0

We add all the numbers together, and all the variables

a-(3419(.041/12+1)^36)=0

We multiply all the terms by the denominator


a*12+1)^36)-(3419(.041=0

We add all the numbers together, and all the variables

a*12=0

Wy multiply elements

12a=0

a=0/12

a=0

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